18+y=6(2-3y+10)+y

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Solution for 18+y=6(2-3y+10)+y equation: 



18+y=6(2-3y+10)+y

We move all terms to the left:

18+y-(6(2-3y+10)+y)=0

We add all the numbers together, and all the variables

y-(6(-3y+12)+y)+18=0



We calculate terms in parentheses: -(6(-3y+12)+y), so:

6(-3y+12)+y

We add all the numbers together, and all the variables

y+6(-3y+12)

We multiply parentheses

y-18y+72

We add all the numbers together, and all the variables

-17y+72

Back to the equation:

-(-17y+72)



We get rid of parentheses

y+17y-72+18=0

We add all the numbers together, and all the variables

18y-54=0

We move all terms containing y to the left, all other terms to the right

18y=54

y=54/18

y=3

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