-(y-6)=3(y-2)+2y

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Solution for -(y-6)=3(y-2)+2y equation: 



-(y-6)=3(y-2)+2y

We move all terms to the left:

-(y-6)-(3(y-2)+2y)=0

We get rid of parentheses

-y-(3(y-2)+2y)+6=0



We calculate terms in parentheses: -(3(y-2)+2y), so:

3(y-2)+2y

We add all the numbers together, and all the variables

2y+3(y-2)

We multiply parentheses

2y+3y-6

We add all the numbers together, and all the variables

5y-6

Back to the equation:

-(5y-6)



We add all the numbers together, and all the variables

-1y-(5y-6)+6=0

We get rid of parentheses

-1y-5y+6+6=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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