20=2(y+2)+2

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Solution for 20=2(y+2)+2 equation: 



20=2(y+2)+2

We move all terms to the left:

20-(2(y+2)+2)=0



We calculate terms in parentheses: -(2(y+2)+2), so:

2(y+2)+2

We multiply parentheses

2y+4+2

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

-2y-6+20=0

We add all the numbers together, and all the variables

-2y+14=0

We move all terms containing y to the left, all other terms to the right

-2y=-14

y=-14/-2

y=+7

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