18+(7x-5)-6-(1-x)=6-(36+x)

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Solution for 18+(7x-5)-6-(1-x)=6-(36+x) equation: 



18+(7x-5)-6-(1-x)=6-(36+x)

We move all terms to the left:

18+(7x-5)-6-(1-x)-(6-(36+x))=0

We add all the numbers together, and all the variables

(7x-5)-(-1x+1)-(6-(x+36))+18-6=0

We add all the numbers together, and all the variables

(7x-5)-(-1x+1)-(6-(x+36))+12=0

We get rid of parentheses

7x+1x-(6-(x+36))-5-1+12=0



We calculate terms in parentheses: -(6-(x+36)), so:

6-(x+36)

determiningTheFunctionDomain
-(x+36)+6

We get rid of parentheses

-x-36+6

We add all the numbers together, and all the variables

-1x-30

Back to the equation:

-(-1x-30)



We add all the numbers together, and all the variables

8x-(-1x-30)+6=0

We get rid of parentheses

8x+1x+30+6=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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