x=(x+3)2+(x-1)2

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Solution for x=(x+3)2+(x-1)2 equation: 



x=(x+3)2+(x-1)2

We move all terms to the left:

x-((x+3)2+(x-1)2)=0



We calculate terms in parentheses: -((x+3)2+(x-1)2), so:

(x+3)2+(x-1)2

We multiply parentheses

2x+2x+6-2

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

x-4x-4=0

We add all the numbers together, and all the variables

-3x-4=0

We move all terms containing x to the left, all other terms to the right

-3x=4

x=4/-3

x=-1+1/3

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