(x+3)*(x+3)+(x-1)*(x-1)=

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Solution for (x+3)*(x+3)+(x-1)*(x-1)= equation: 



(x+3)(x+3)+(x-1)(x-1)=

We move all terms to the left:

(x+3)(x+3)+(x-1)(x-1)-()=0

We add all the numbers together, and all the variables

(x+3)(x+3)+(x-1)(x-1)=0

We multiply parentheses ..

(+x^2+3x+3x+9)+(x-1)(x-1)=0

We get rid of parentheses

x^2+3x+3x+(x-1)(x-1)+9=0

We multiply parentheses ..

x^2+(+x^2-1x-1x+1)+3x+3x+9=0

We add all the numbers together, and all the variables

x^2+(+x^2-1x-1x+1)+6x+9=0

We get rid of parentheses

x^2+x^2-1x-1x+6x+1+9=0

We add all the numbers together, and all the variables

2x^2+4x+10=0

a = 2; b = 4; c = +10;
Δ = b2-4ac
Δ = 42-4·2·10
Δ = -64
Delta is less than zero, so there is no solution for the equation

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