17(b+3b)=18+(4b-1)

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Solution for 17(b+3b)=18+(4b-1) equation: 



17(b+3b)=18+(4b-1)

We move all terms to the left:

17(b+3b)-(18+(4b-1))=0

We add all the numbers together, and all the variables

17(+4b)-(18+(4b-1))=0

We multiply parentheses

68b-(18+(4b-1))=0



We calculate terms in parentheses: -(18+(4b-1)), so:

18+(4b-1)

determiningTheFunctionDomain
(4b-1)+18

We get rid of parentheses

4b-1+18

We add all the numbers together, and all the variables

4b+17

Back to the equation:

-(4b+17)



We get rid of parentheses

68b-4b-17=0

We add all the numbers together, and all the variables

64b-17=0

We move all terms containing b to the left, all other terms to the right

64b=17

b=17/64

b=17/64

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