-3t(2t-4)+2t=5t-4

Solution for -3t(2t-4)+2t=5t-4 equation:

-3t(2t-4)+2t=5t-4

We move all terms to the left:

-3t(2t-4)+2t-(5t-4)=0

We add all the numbers together, and all the variables

2t-3t(2t-4)-(5t-4)=0

We multiply parentheses

-6t^2+2t+12t-(5t-4)=0

We get rid of parentheses

-6t^2+2t+12t-5t+4=0

We add all the numbers together, and all the variables

-6t^2+9t+4=0

a = -6; b = 9; c = +4;
Δ = b2-4ac
Δ = 92-4·(-6)·4
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{177}}{2*-6}=\frac{-9-\sqrt{177}}{-12}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{177}}{2*-6}=\frac{-9+\sqrt{177}}{-12}
$