3(x+4)+2=2+5(x+-4)

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Solution for 3(x+4)+2=2+5(x+-4) equation:



3(x+4)+2=2+5(x+-4)
We move all terms to the left:
3(x+4)+2-(2+5(x+-4))=0
We add all the numbers together, and all the variables
3(x+4)-(2+5(x-4))+2=0
We multiply parentheses
3x-(2+5(x-4))+12+2=0
We calculate terms in parentheses: -(2+5(x-4)), so:
2+5(x-4)
determiningTheFunctionDomain 5(x-4)+2
We multiply parentheses
5x-20+2
We add all the numbers together, and all the variables
5x-18
Back to the equation:
-(5x-18)
We add all the numbers together, and all the variables
3x-(5x-18)+14=0
We get rid of parentheses
3x-5x+18+14=0
We add all the numbers together, and all the variables
-2x+32=0
We move all terms containing x to the left, all other terms to the right
-2x=-32
x=-32/-2
x=+16

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