If it's not what You are looking for type in the equation solver your own equation and let us solve it.
16x^2+8x-8=0
a = 16; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·16·(-8)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*16}=\frac{-32}{32} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*16}=\frac{16}{32} =1/2 $
| 268-c=225 | | 23+4(j-4)-j=11 | | 6a-3(3-3a)=6a= | | 25-h=19 | | 2x-10+3x=25* | | 3(h+1)-5=-1 | | -7x-5=60 | | 3x+6=8x–9 | | -4(y+-5)+8=12 | | x+6÷3=x+4 | | 45-a=21 | | j+45/9=8 | | (x+8)+(2x+7)=90 | | 2x+76+78+42=180 | | 3x+4x=5+16 | | -2/w=-1 | | -4(n+10)=-16 | | 6r-r-2r+5r=8 | | 6a-20=4 | | 70+90+4x=180 | | 2(3+4y)=46 | | 11-2x+8x+5=33 | | j/3+3=9 | | 3x+5+7=7x-3 | | x+4x+(x+8)=20 | | 2(j-8)=12 | | -3(-2x+7)=-9 | | 8(x+2)-3(x+4)=6(x-7)+8 | | 6x+7x=-4+2x | | 15=360/n | | -25x^2+158x-36=0 | | 4x+20+2(x-7)=04 |