4x+20+2(x-7)=04

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Solution for 4x+20+2(x-7)=04 equation: 



4x+20+2(x-7)=04

We move all terms to the left:

4x+20+2(x-7)-(04)=0

We add all the numbers together, and all the variables

4x+2(x-7)+16=0

We multiply parentheses

4x+2x-14+16=0

We add all the numbers together, and all the variables

6x+2=0

We move all terms containing x to the left, all other terms to the right

6x=-2

x=-2/6

x=-1/3

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