8(x+2)-3(x+4)=6(x-7)+8

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Solution for 8(x+2)-3(x+4)=6(x-7)+8 equation:



8(x+2)-3(x+4)=6(x-7)+8
We move all terms to the left:
8(x+2)-3(x+4)-(6(x-7)+8)=0
We multiply parentheses
8x-3x-(6(x-7)+8)+16-12=0
We calculate terms in parentheses: -(6(x-7)+8), so:
6(x-7)+8
We multiply parentheses
6x-42+8
We add all the numbers together, and all the variables
6x-34
Back to the equation:
-(6x-34)
We add all the numbers together, and all the variables
5x-(6x-34)+4=0
We get rid of parentheses
5x-6x+34+4=0
We add all the numbers together, and all the variables
-1x+38=0
We move all terms containing x to the left, all other terms to the right
-x=-38
x=-38/-1
x=+38

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