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16x^2+24x=-9
We move all terms to the left:
16x^2+24x-(-9)=0
We add all the numbers together, and all the variables
16x^2+24x+9=0
a = 16; b = 24; c = +9;
Δ = b2-4ac
Δ = 242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-24}{32}=-3/4$
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