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3x(3x+4x)=2100
We move all terms to the left:
3x(3x+4x)-(2100)=0
We add all the numbers together, and all the variables
3x(+7x)-2100=0
We multiply parentheses
21x^2-2100=0
a = 21; b = 0; c = -2100;
Δ = b2-4ac
Δ = 02-4·21·(-2100)
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{176400}=420$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-420}{2*21}=\frac{-420}{42} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+420}{2*21}=\frac{420}{42} =10 $
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