(2x)/7=(x-2)/14

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Solution for (2x)/7=(x-2)/14 equation: 



(2x)/7=(x-2)/14

We move all terms to the left:

(2x)/7-((x-2)/14)=0

We calculate fractions


28x^2/()+(-((x-2)*7)/()=0



We calculate terms in parentheses: +(-((x-2)*7)/(), so:

-((x-2)*7)/(

We multiply all the terms by the denominator


-((x-2)*7)



We calculate terms in parentheses: -((x-2)*7), so:

(x-2)*7

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

-7x+14

Back to the equation:

+(-7x+14)



We get rid of parentheses

28x^2/()-7x+14=0

We multiply all the terms by the denominator


28x^2-7x*()+14*()=0

We add all the numbers together, and all the variables

28x^2-7x*()=0

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