16=2(t-1)+

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Solution for 16=2(t-1)+ equation: 



16=2(t-1)+

We move all terms to the left:

16-(2(t-1)+)=0



We calculate terms in parentheses: -(2(t-1)+), so:

2(t-1)+

We add all the numbers together, and all the variables

2(t-1)

We multiply parentheses

2t-2

Back to the equation:

-(2t-2)



We get rid of parentheses

-2t+2+16=0

We add all the numbers together, and all the variables

-2t+18=0

We move all terms containing t to the left, all other terms to the right

-2t=-18

t=-18/-2

t=+9

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