3(4y+1)-11=6(6y+5)+8

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Solution for 3(4y+1)-11=6(6y+5)+8 equation: 



3(4y+1)-11=6(6y+5)+8

We move all terms to the left:

3(4y+1)-11-(6(6y+5)+8)=0

We multiply parentheses

12y-(6(6y+5)+8)+3-11=0



We calculate terms in parentheses: -(6(6y+5)+8), so:

6(6y+5)+8

We multiply parentheses

36y+30+8

We add all the numbers together, and all the variables

36y+38

Back to the equation:

-(36y+38)



We add all the numbers together, and all the variables

12y-(36y+38)-8=0

We get rid of parentheses

12y-36y-38-8=0

We add all the numbers together, and all the variables

-24y-46=0

We move all terms containing y to the left, all other terms to the right

-24y=46

y=46/-24

y=-1+11/12

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