(2(z-8)/12)=3/2

Solution for (2(z-8)/12)=3/2 equation:

(2(z-8)/12)=3/2

We move all terms to the left:

(2(z-8)/12)-(3/2)=0

We add all the numbers together, and all the variables

(2(z-8)/12)-(+3/2)=0

We get rid of parentheses

(2(z-8)/12)-3/2=0

We calculate fractions


((2(z-8)*2)/()+()/()=0


We calculate terms in parentheses: +((2(z-8)*2)/()+()/(), so:

(2(z-8)*2)/()+()/(

We add all the numbers together, and all the variables

(2(z-8)*2)/()+1

We multiply all the terms by the denominator


(2(z-8)*2)+1*()


We calculate terms in parentheses: +(2(z-8)*2), so:

2(z-8)*2

We multiply parentheses

4z-32

Back to the equation:

+(4z-32)


We add all the numbers together, and all the variables

(4z-32)

We get rid of parentheses

4z-32

Back to the equation:

+(4z-32)


We get rid of parentheses

4z-32=0

We move all terms containing z to the left, all other terms to the right

4z=32

z=32/4

z=8