16=-4y(y+3)

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Solution for 16=-4y(y+3) equation: 



16=-4y(y+3)

We move all terms to the left:

16-(-4y(y+3))=0



We calculate terms in parentheses: -(-4y(y+3)), so:

-4y(y+3)

We multiply parentheses

-4y^2-12y

Back to the equation:

-(-4y^2-12y)



We get rid of parentheses

4y^2+12y+16=0

a = 4; b = 12; c = +16;
Δ = b2-4ac
Δ = 122-4·4·16
Δ = -112
Delta is less than zero, so there is no solution for the equation

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