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0.5x^2+2.5x=25
We move all terms to the left:
0.5x^2+2.5x-(25)=0
a = 0.5; b = 2.5; c = -25;
Δ = b2-4ac
Δ = 2.52-4·0.5·(-25)
Δ = 56.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{56.25}}{2*0.5}=\frac{-2.5-\sqrt{56.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{56.25}}{2*0.5}=\frac{-2.5+\sqrt{56.25}}{1} $
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