-4y(y+3)=16

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Solution for -4y(y+3)=16 equation: 



-4y(y+3)=16

We move all terms to the left:

-4y(y+3)-(16)=0

We multiply parentheses

-4y^2-12y-16=0

a = -4; b = -12; c = -16;
Δ = b2-4ac
Δ = -122-4·(-4)·(-16)
Δ = -112
Delta is less than zero, so there is no solution for the equation

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