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169=2x^2+14x
We move all terms to the left:
169-(2x^2+14x)=0
We get rid of parentheses
-2x^2-14x+169=0
a = -2; b = -14; c = +169;
Δ = b2-4ac
Δ = -142-4·(-2)·169
Δ = 1548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1548}=\sqrt{36*43}=\sqrt{36}*\sqrt{43}=6\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6\sqrt{43}}{2*-2}=\frac{14-6\sqrt{43}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6\sqrt{43}}{2*-2}=\frac{14+6\sqrt{43}}{-4} $
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