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(7x-6)(3x+4)=0
We multiply parentheses ..
(+21x^2+28x-18x-24)=0
We get rid of parentheses
21x^2+28x-18x-24=0
We add all the numbers together, and all the variables
21x^2+10x-24=0
a = 21; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·21·(-24)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-46}{2*21}=\frac{-56}{42} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+46}{2*21}=\frac{36}{42} =6/7 $
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