15=-3(z+2)+1

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Solution for 15=-3(z+2)+1 equation: 



15=-3(z+2)+1

We move all terms to the left:

15-(-3(z+2)+1)=0



We calculate terms in parentheses: -(-3(z+2)+1), so:

-3(z+2)+1

We multiply parentheses

-3z-6+1

We add all the numbers together, and all the variables

-3z-5

Back to the equation:

-(-3z-5)



We get rid of parentheses

3z+5+15=0

We add all the numbers together, and all the variables

3z+20=0

We move all terms containing z to the left, all other terms to the right

3z=-20

z=-20/3

z=-6+2/3

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