3(c-5)=6+2(c-7)

Solution for 3(c-5)=6+2(c-7) equation:

3(c-5)=6+2(c-7)

We move all terms to the left:

3(c-5)-(6+2(c-7))=0

We multiply parentheses

3c-(6+2(c-7))-15=0


We calculate terms in parentheses: -(6+2(c-7)), so:

6+2(c-7)

determiningTheFunctionDomain
2(c-7)+6

We multiply parentheses

2c-14+6

We add all the numbers together, and all the variables

2c-8

Back to the equation:

-(2c-8)


We get rid of parentheses

3c-2c+8-15=0

We add all the numbers together, and all the variables

c-7=0

We move all terms containing c to the left, all other terms to the right

c=7