2(z+4)+(z+1)=5(z+2)-(3z+1)

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Solution for 2(z+4)+(z+1)=5(z+2)-(3z+1) equation: 



2(z+4)+(z+1)=5(z+2)-(3z+1)

We move all terms to the left:

2(z+4)+(z+1)-(5(z+2)-(3z+1))=0

We multiply parentheses

2z+(z+1)-(5(z+2)-(3z+1))+8=0

We get rid of parentheses

2z+z-(5(z+2)-(3z+1))+1+8=0



We calculate terms in parentheses: -(5(z+2)-(3z+1)), so:

5(z+2)-(3z+1)

We multiply parentheses

5z-(3z+1)+10

We get rid of parentheses

5z-3z-1+10

We add all the numbers together, and all the variables

2z+9

Back to the equation:

-(2z+9)



We add all the numbers together, and all the variables

3z-(2z+9)+9=0

We get rid of parentheses

3z-2z-9+9=0

We add all the numbers together, and all the variables

z=0

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