15=(4x+4)+3x-3

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Solution for 15=(4x+4)+3x-3 equation: 



15=(4x+4)+3x-3

We move all terms to the left:

15-((4x+4)+3x-3)=0



We calculate terms in parentheses: -((4x+4)+3x-3), so:

(4x+4)+3x-3

We add all the numbers together, and all the variables

3x+(4x+4)-3

We get rid of parentheses

3x+4x+4-3

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We get rid of parentheses

-7x-1+15=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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