4(2q-3)=(8q-12)

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Solution for 4(2q-3)=(8q-12) equation: 



4(2q-3)=(8q-12)

We move all terms to the left:

4(2q-3)-((8q-12))=0

We multiply parentheses

8q-((8q-12))-12=0



We calculate terms in parentheses: -((8q-12)), so:

(8q-12)

We get rid of parentheses

8q-12

Back to the equation:

-(8q-12)



We get rid of parentheses

8q-8q+12-12=0

We add all the numbers together, and all the variables

=0

q=0/1

q=0

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