-10(x+2)=6(-x+12)

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Solution for -10(x+2)=6(-x+12) equation: 



-10(x+2)=6(-x+12)

We move all terms to the left:

-10(x+2)-(6(-x+12))=0

We add all the numbers together, and all the variables

-10(x+2)-(6(-1x+12))=0

We multiply parentheses

-10x-(6(-1x+12))-20=0



We calculate terms in parentheses: -(6(-1x+12)), so:

6(-1x+12)

We multiply parentheses

-6x+72

Back to the equation:

-(-6x+72)



We get rid of parentheses

-10x+6x-72-20=0

We add all the numbers together, and all the variables

-4x-92=0

We move all terms containing x to the left, all other terms to the right

-4x=92

x=92/-4

x=-23

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