-4(4v-2)+3v=2(v+9)

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Solution for -4(4v-2)+3v=2(v+9) equation: 



-4(4v-2)+3v=2(v+9)

We move all terms to the left:

-4(4v-2)+3v-(2(v+9))=0

We add all the numbers together, and all the variables

3v-4(4v-2)-(2(v+9))=0

We multiply parentheses

3v-16v-(2(v+9))+8=0



We calculate terms in parentheses: -(2(v+9)), so:

2(v+9)

We multiply parentheses

2v+18

Back to the equation:

-(2v+18)



We add all the numbers together, and all the variables

-13v-(2v+18)+8=0

We get rid of parentheses

-13v-2v-18+8=0

We add all the numbers together, and all the variables

-15v-10=0

We move all terms containing v to the left, all other terms to the right

-15v=10

v=10/-15

v=-2/3

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