15=(2/3)(4x+9)

Solution for 15=(2/3)(4x+9) equation:

15=(2/3)(4x+9)

We move all terms to the left:

15-((2/3)(4x+9))=0


Domain of the equation: 3)(4x+9))!=0

x∈R


We add all the numbers together, and all the variables

-((+2/3)(4x+9))+15=0

We multiply parentheses ..

-((+8x^2+2/3*9))+15=0

We multiply all the terms by the denominator


-((+8x^2+2+15*3*9))=0


We calculate terms in parentheses: -((+8x^2+2+15*3*9)), so:

(+8x^2+2+15*3*9)

We get rid of parentheses

8x^2+2+15*3*9

We add all the numbers together, and all the variables

8x^2+407

Back to the equation:

-(8x^2+407)


We get rid of parentheses

-8x^2-407=0

a = -8; b = 0; c = -407;
Δ = b2-4ac
Δ = 02-4·(-8)·(-407)
Δ = -13024
Delta is less than zero, so there is no solution for the equation