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325/100+1/2x+11/3+5/6x=511/12
We move all terms to the left:
325/100+1/2x+11/3+5/6x-(511/12)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
1/2x+5/6x+325/100+11/3-(+511/12)=0
We get rid of parentheses
1/2x+5/6x+325/100+11/3-511/12=0
We calculate fractions
(-11037600x^2)/43200x^2+842400x^2/43200x^2+950400x^2/43200x^2+21600x/43200x^2+36000x/43200x^2=0
We multiply all the terms by the denominator
(-11037600x^2)+842400x^2+950400x^2+21600x+36000x=0
We add all the numbers together, and all the variables
1792800x^2+(-11037600x^2)+57600x=0
We get rid of parentheses
1792800x^2-11037600x^2+57600x=0
We add all the numbers together, and all the variables
-9244800x^2+57600x=0
a = -9244800; b = 57600; c = 0;
Δ = b2-4ac
Δ = 576002-4·(-9244800)·0
Δ = 3317760000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3317760000}=57600$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57600)-57600}{2*-9244800}=\frac{-115200}{-18489600} =2/321 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57600)+57600}{2*-9244800}=\frac{0}{-18489600} =0 $
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