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5=1/3(3x-9)+8
We move all terms to the left:
5-(1/3(3x-9)+8)=0
Domain of the equation: 3(3x-9)+8)!=0We multiply all the terms by the denominator
x∈R
-(1+5*3(3x-9)+8)=0
We calculate terms in parentheses: -(1+5*3(3x-9)+8), so:We add all the numbers together, and all the variables
1+5*3(3x-9)+8
determiningTheFunctionDomain 5*3(3x-9)+1+8
We add all the numbers together, and all the variables
5*3(3x-9)+9
Wy multiply elements
15x(3+9
Back to the equation:
-(15x(3+9)
-(15x12=0
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