15-2(x+5)=3x-10(x-4)

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Solution for 15-2(x+5)=3x-10(x-4) equation: 



15-2(x+5)=3x-10(x-4)

We move all terms to the left:

15-2(x+5)-(3x-10(x-4))=0

We multiply parentheses

-2x-(3x-10(x-4))-10+15=0



We calculate terms in parentheses: -(3x-10(x-4)), so:

3x-10(x-4)

We multiply parentheses

3x-10x+40

We add all the numbers together, and all the variables

-7x+40

Back to the equation:

-(-7x+40)



We add all the numbers together, and all the variables

-2x-(-7x+40)+5=0

We get rid of parentheses

-2x+7x-40+5=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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