3(y+5)=-7(2y-1)+7y

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Solution for 3(y+5)=-7(2y-1)+7y equation: 



3(y+5)=-7(2y-1)+7y

We move all terms to the left:

3(y+5)-(-7(2y-1)+7y)=0

We multiply parentheses

3y-(-7(2y-1)+7y)+15=0



We calculate terms in parentheses: -(-7(2y-1)+7y), so:

-7(2y-1)+7y

We add all the numbers together, and all the variables

7y-7(2y-1)

We multiply parentheses

7y-14y+7

We add all the numbers together, and all the variables

-7y+7

Back to the equation:

-(-7y+7)



We get rid of parentheses

3y+7y-7+15=0

We add all the numbers together, and all the variables

10y+8=0

We move all terms containing y to the left, all other terms to the right

10y=-8

y=-8/10

y=-4/5

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