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3(2x-4)=-6(2-x)
We move all terms to the left:
3(2x-4)-(-6(2-x))=0
We add all the numbers together, and all the variables
3(2x-4)-(-6(-1x+2))=0
We multiply parentheses
6x-(-6(-1x+2))-12=0
We calculate terms in parentheses: -(-6(-1x+2)), so:We get rid of parentheses
-6(-1x+2)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
6x-6x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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