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15-(7x+4)=2x-5(x-3)
We move all terms to the left:
15-(7x+4)-(2x-5(x-3))=0
We get rid of parentheses
-7x-(2x-5(x-3))-4+15=0
We calculate terms in parentheses: -(2x-5(x-3)), so:We add all the numbers together, and all the variables
2x-5(x-3)
We multiply parentheses
2x-5x+15
We add all the numbers together, and all the variables
-3x+15
Back to the equation:
-(-3x+15)
-7x-(-3x+15)+11=0
We get rid of parentheses
-7x+3x-15+11=0
We add all the numbers together, and all the variables
-4x-4=0
We move all terms containing x to the left, all other terms to the right
-4x=4
x=4/-4
x=-1
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