4(t-2)+4t=4(2t+4)-13

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Solution for 4(t-2)+4t=4(2t+4)-13 equation: 



4(t-2)+4t=4(2t+4)-13

We move all terms to the left:

4(t-2)+4t-(4(2t+4)-13)=0

We add all the numbers together, and all the variables

4t+4(t-2)-(4(2t+4)-13)=0

We multiply parentheses

4t+4t-(4(2t+4)-13)-8=0



We calculate terms in parentheses: -(4(2t+4)-13), so:

4(2t+4)-13

We multiply parentheses

8t+16-13

We add all the numbers together, and all the variables

8t+3

Back to the equation:

-(8t+3)



We add all the numbers together, and all the variables

8t-(8t+3)-8=0

We get rid of parentheses

8t-8t-3-8=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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