148-(x+(4x-5))=2(x+3)

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Solution for 148-(x+(4x-5))=2(x+3) equation: 



148-(x+(4x-5))=2(x+3)

We move all terms to the left:

148-(x+(4x-5))-(2(x+3))=0



We calculate terms in parentheses: -(x+(4x-5)), so:

x+(4x-5)

We get rid of parentheses

x+4x-5

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)





We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

-5x-2x+5-6+148=0

We add all the numbers together, and all the variables

-7x+147=0

We move all terms containing x to the left, all other terms to the right

-7x=-147

x=-147/-7

x=+21

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