-5(2y+1)-2(3-y)=2(3y+1)-5

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Solution for -5(2y+1)-2(3-y)=2(3y+1)-5 equation: 



-5(2y+1)-2(3-y)=2(3y+1)-5

We move all terms to the left:

-5(2y+1)-2(3-y)-(2(3y+1)-5)=0

We add all the numbers together, and all the variables

-5(2y+1)-2(-1y+3)-(2(3y+1)-5)=0

We multiply parentheses

-10y+2y-(2(3y+1)-5)-5-6=0



We calculate terms in parentheses: -(2(3y+1)-5), so:

2(3y+1)-5

We multiply parentheses

6y+2-5

We add all the numbers together, and all the variables

6y-3

Back to the equation:

-(6y-3)



We add all the numbers together, and all the variables

-8y-(6y-3)-11=0

We get rid of parentheses

-8y-6y+3-11=0

We add all the numbers together, and all the variables

-14y-8=0

We move all terms containing y to the left, all other terms to the right

-14y=8

y=8/-14

y=-4/7

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