140=(8-2x)(12+2x)

Solution for 140=(8-2x)(12+2x) equation:

140=(8-2x)(12+2x)

We move all terms to the left:

140-((8-2x)(12+2x))=0

We add all the numbers together, and all the variables

-((-2x+8)(2x+12))+140=0

We multiply parentheses ..

-((-4x^2-24x+16x+96))+140=0


We calculate terms in parentheses: -((-4x^2-24x+16x+96)), so:

(-4x^2-24x+16x+96)

We get rid of parentheses

-4x^2-24x+16x+96

We add all the numbers together, and all the variables

-4x^2-8x+96

Back to the equation:

-(-4x^2-8x+96)


We get rid of parentheses

4x^2+8x-96+140=0

We add all the numbers together, and all the variables

4x^2+8x+44=0

a = 4; b = 8; c = +44;
Δ = b2-4ac
Δ = 82-4·4·44
Δ = -640
Delta is less than zero, so there is no solution for the equation