8+(x+3)=6-(x+8)

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Solution for 8+(x+3)=6-(x+8) equation: 



8+(x+3)=6-(x+8)

We move all terms to the left:

8+(x+3)-(6-(x+8))=0

We get rid of parentheses

x-(6-(x+8))+3+8=0



We calculate terms in parentheses: -(6-(x+8)), so:

6-(x+8)

determiningTheFunctionDomain
-(x+8)+6

We get rid of parentheses

-x-8+6

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We add all the numbers together, and all the variables

x-(-1x-2)+11=0

We get rid of parentheses

x+1x+2+11=0

We add all the numbers together, and all the variables

2x+13=0

We move all terms containing x to the left, all other terms to the right

2x=-13

x=-13/2

x=-6+1/2

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