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X+1/3X=165
We move all terms to the left:
X+1/3X-(165)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-165*3X+1=0
Wy multiply elements
3X^2-495X+1=0
a = 3; b = -495; c = +1;
Δ = b2-4ac
Δ = -4952-4·3·1
Δ = 245013
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-495)-\sqrt{245013}}{2*3}=\frac{495-\sqrt{245013}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-495)+\sqrt{245013}}{2*3}=\frac{495+\sqrt{245013}}{6} $
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