140+p=3(100-p)

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Solution for 140+p=3(100-p) equation: 



140+p=3(100-p)

We move all terms to the left:

140+p-(3(100-p))=0

We add all the numbers together, and all the variables

p-(3(-1p+100))+140=0



We calculate terms in parentheses: -(3(-1p+100)), so:

3(-1p+100)

We multiply parentheses

-3p+300

Back to the equation:

-(-3p+300)



We get rid of parentheses

p+3p-300+140=0

We add all the numbers together, and all the variables

4p-160=0

We move all terms containing p to the left, all other terms to the right

4p=160

p=160/4

p=40

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