4(3y-5)=(11y+4)

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Solution for 4(3y-5)=(11y+4) equation: 



4(3y-5)=(11y+4)

We move all terms to the left:

4(3y-5)-((11y+4))=0

We multiply parentheses

12y-((11y+4))-20=0



We calculate terms in parentheses: -((11y+4)), so:

(11y+4)

We get rid of parentheses

11y+4

Back to the equation:

-(11y+4)



We get rid of parentheses

12y-11y-4-20=0

We add all the numbers together, and all the variables

y-24=0

We move all terms containing y to the left, all other terms to the right

y=24

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