19-(20-5x)=3x+(8-4x)

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Solution for 19-(20-5x)=3x+(8-4x) equation: 



19-(20-5x)=3x+(8-4x)

We move all terms to the left:

19-(20-5x)-(3x+(8-4x))=0

We add all the numbers together, and all the variables

-(-5x+20)-(3x+(-4x+8))+19=0

We get rid of parentheses

5x-(3x+(-4x+8))-20+19=0



We calculate terms in parentheses: -(3x+(-4x+8)), so:

3x+(-4x+8)

We get rid of parentheses

3x-4x+8

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

5x-(-1x+8)-1=0

We get rid of parentheses

5x+1x-8-1=0

We add all the numbers together, and all the variables

6x-9=0

We move all terms containing x to the left, all other terms to the right

6x=9

x=9/6

x=1+1/2

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