13x-2(x+4)=8x+J1

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Solution for 13x-2(x+4)=8x+J1 equation: 



13x-2(x+4)=8x+1

We move all terms to the left:

13x-2(x+4)-(8x+1)=0

We multiply parentheses

13x-2x-(8x+1)-8=0

We get rid of parentheses

13x-2x-8x-1-8=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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