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7u=-4u^2
We move all terms to the left:
7u-(-4u^2)=0
We get rid of parentheses
4u^2+7u=0
a = 4; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·4·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*4}=\frac{-14}{8} =-1+3/4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*4}=\frac{0}{8} =0 $
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