(2y)+(3+(y-3))+(2y)=15

Solution for (2y)+(3+(y-3))+(2y)=15 equation:

(2y)+(3+(y-3))+(2y)=15

We move all terms to the left:

(2y)+(3+(y-3))+(2y)-(15)=0

We add all the numbers together, and all the variables

4y+(3+(y-3))-15=0


We calculate terms in parentheses: +(3+(y-3)), so:

3+(y-3)

determiningTheFunctionDomain
(y-3)+3

We get rid of parentheses

y-3+3

We add all the numbers together, and all the variables

y

Back to the equation:

+(y)


We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3