3q-16q=7+2(-9q-3)

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Solution for 3q-16q=7+2(-9q-3) equation: 



3q-16q=7+2(-9q-3)

We move all terms to the left:

3q-16q-(7+2(-9q-3))=0

We add all the numbers together, and all the variables

-13q-(7+2(-9q-3))=0



We calculate terms in parentheses: -(7+2(-9q-3)), so:

7+2(-9q-3)

determiningTheFunctionDomain
2(-9q-3)+7

We multiply parentheses

-18q-6+7

We add all the numbers together, and all the variables

-18q+1

Back to the equation:

-(-18q+1)



We get rid of parentheses

-13q+18q-1=0

We add all the numbers together, and all the variables

5q-1=0

We move all terms containing q to the left, all other terms to the right

5q=1

q=1/5

q=1/5

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